albums_labels

2 rows where label_id = 1827

✎ View and edit SQL

This data as json, CSV (advanced)

CREATE TABLE albums_labels (
	album_id integer NOT NULL,
	label_id integer NOT NULL,
	FOREIGN KEY(album_id) REFERENCES albums(id),
	FOREIGN KEY(label_id) REFERENCES labels(id),
	UNIQUE(album_id,label_id)
);