reviews_albums

1 row where album_id = 18363

✎ View and edit SQL

This data as json, CSV (advanced)

CREATE TABLE reviews_albums (
	review_id integer NOT NULL,
	album_id integer NOT NULL,
	FOREIGN KEY(review_id) REFERENCES reviews(id),
	FOREIGN KEY(album_id) REFERENCES albums(id),
	UNIQUE(review_id, album_id)
);